Q. 44.4( 148 Votes )

The diagonal of a quadrilateral shaped field is 24 m and the perpendiculars dropped on it from the remaining opposite vertices are 8 m and 13 m. Find the area of the field.


Answer :

Area of upper triangle = 1/2 × height × base


= 1/2 × 13 × 24


= 156 m2


Area of lower triangle = 1/2 × height × base


= 1/2 × 8 × 24


= 96 m2


Area of the field = 156 + 96 = 252 m2


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