Q. 45.0( 1 Vote )

P is in the exter

Answer :

Given OP = 34, PQ = 16


OQ is the radius of the circle.


Since PQ is a tangent to the circle, OQ PQ.



In right angled ΔOQP,


By Pythagoras Theorem,


OP2 = PQ2 + OQ2


342 = 162 + OQ2


OQ2 = 1156 – 256


OQ2 = 900


OQ = 30


Diameter of circle = 2r = 2 × OQ = 2 × 30 = 60


Diameter = 60


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