Q. 34.1( 224 Votes )

Length of the fence of a trapezium shaped field ABCD is 120 m. If BC = 48 m, CD = 17 m and AD = 40 m, find the area of this field. Side AB is perpendicular to the parallel sides AD and BC


Answer :

If a perpendicular from D to BC is drawn then it will be equal to AB,

then EC = 48-40 = 8 m.


In ΔDEC,
By Pythagoras theorem
DE2 = DC2-EC2


DE2 = 172 - 82 = 289 - 64 = 225


Or, DE = 15 m


Area of Trapezium = 1/2 × (sum of parallel sides) × height


= 1/2 × (48 + 40) × 15


= 660 m2

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Area of PolygonsArea of PolygonsArea of Polygons41 mins
Quiz | Imp. Qs on PolyhedronsQuiz | Imp. Qs on PolyhedronsQuiz | Imp. Qs on Polyhedrons38 mins
Quiz | MensurationQuiz | MensurationQuiz | Mensuration45 mins
Quiz | MensurationQuiz | MensurationQuiz | Mensuration43 mins
NCERT | Surface Area of Solid ShapesNCERT | Surface Area of Solid ShapesNCERT | Surface Area of Solid Shapes39 mins
NCERT | Imp. Qs. of MensurationNCERT | Imp. Qs. of MensurationNCERT | Imp. Qs. of Mensuration53 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :