Q. 34.1( 224 Votes )

# Length of the fence of a trapezium shaped field ABCD is 120 m. If BC = 48 m, CD = 17 m and AD = 40 m, find the area of this field. Side AB is perpendicular to the parallel sides AD and BC

Answer :

If a perpendicular from D to BC is drawn then it will be equal to AB,

then EC = 48-40 = 8 m.

In ΔDEC,

By Pythagoras theorem

DE^{2} = DC^{2}-EC^{2}

DE^{2} = 17^{2} - 8^{2} = 289 - 64 = 225

Or, DE = 15 m

Area of Trapezium = 1/2 × (sum of parallel sides) × height

= 1/2 × (48 + 40) × 15

= 660 m^{2}

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