Q. 3
In the given figure points L, M and N respectively lie on OA, OB and OC such that LM || AB and MN || BC. Then, show that LN || AC.
Answer :
In OAB & OLM
LM||AB
…(1) |By Basic Proportionality Theorem(BPT)
In ΔOMN & ΔOBC,
MN||BC
…(2) |By BPT
From (1)&(2)
…(3)
In ΔOLN & ΔOAC
⇒ LN||AC by Converse of BPT
Hence, proved.
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