Answer :

Given the radius of larger circle = 73 = OB and radius of smaller circle = 55 = OM



Since AB is a tangent, OM AB.


Consider ΔOMB,


Here, OMB is a right angle.


By Pythagoras Theorem,


OB2 = OM2 + MB2


MB2 = OB2 – OM2


= 732 – 552


We know that a2 – b2 = (a + b) (a – b)


MB2 = (73 + 55) (73 – 55)


= (128) (18)


= 2304


MB = 48


Now, length of chord = AB = 2MB = 2 (48) = 96


The length of chord is 96.


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