Q. 2

# Two concentric ci

Given the radius of larger circle = 73 = OB and radius of smaller circle = 55 = OM Since AB is a tangent, OM AB.

Consider ΔOMB,

Here, OMB is a right angle.

By Pythagoras Theorem,

OB2 = OM2 + MB2

MB2 = OB2 – OM2

= 732 – 552

We know that a2 – b2 = (a + b) (a – b)

MB2 = (73 + 55) (73 – 55)

= (128) (18)

= 2304

MB = 48

Now, length of chord = AB = 2MB = 2 (48) = 96

The length of chord is 96.

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