Q. 114.3( 207 Votes )

Diagram of the ad

Answer :

Here two of given figures (I) and (II) are similar in dimensions.
we know area of trapezium = (1/2) × (sum of parallel sides) × height


And also figures (III) and (IV) are similar in dimensions.



For trapezium I, 2 h = 24 - 16, 2 h = 8, h = 4

Area of figure (I) = Area of trapezium


= 1/2 (a + b) h


= 1/2 (28 + 20) × 4


= 96 cm2


Also Area of figure (II) = 96 cm2


Now Area of figure (III)


= Area of trapezium = = 1/2 (24 + 16) × 4


= 80 cm2


Also Area of figure (IV) = 80 cm2

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