# Diagram of the adjacent picture frame has outer dimensions =24 cm × 28 cm and inner dimensions 16 cm × 20 cm. Find the area of each section of the frame, if the width of each section is same.

Here two of given figures (I) and (II) are similar in dimensions.
we know area of trapezium = (1/2) × (sum of parallel sides) × height

And also figures (III) and (IV) are similar in dimensions.

For trapezium I, 2 h = 24 - 16, 2 h = 8, h = 4

Area of figure (I) = Area of trapezium

= 1/2 (a + b) h

= 1/2 (28 + 20) × 4

= 96 cm2

Also Area of figure (II) = 96 cm2

Now Area of figure (III)

= Area of trapezium = = 1/2 (24 + 16) × 4

= 80 cm2

Also Area of figure (IV) = 80 cm2

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