Answer :

Here two of given figures (I) and (II) are similar in dimensions.

we know area of trapezium = (1/2) × (sum of parallel sides) × height

And also figures (III) and (IV) are similar in dimensions.

For trapezium I, 2 h = 24 - 16, 2 h = 8, h = 4

Area of figure (I) = Area of trapezium

= 1/2 (a + b) h

= 1/2 (28 + 20) × 4

= 96 cm^{2}

Also Area of figure (II) = 96 cm^{2}

Now Area of figure (III)

= Area of trapezium = = 1/2 (24 + 16) × 4

= 80 cm^{2}

Also Area of figure (IV) = 80 cm^{2}

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