Q. 95.0( 1 Vote )
P is a point in the exterior of a circle having centre 0 and radius 24. OP = 25. A tangent from P touches the circle at Q. Find PQ.
Given P lies in the exterior of a circle having centre O and PQ is a tangent.
∴ OQ ⊥ PQ
Also given OP = 25 and OQ = 24.
∠OQP = 90°
By Pythagoras Theorem,
⇒ OP2 = OQ2 + PQ2
⇒ 252 = 242 + PQ2
⇒ PQ2 = 625 – 576
∴ PQ = 7
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