Q. 7 H5.0( 3 Votes )

# Solve the followi

Ideas required to solve the problem:

The general solution of any trigonometric equation is given as –

• sin x = sin y, implies x = nπ + (– 1)ny, where n Z.

• cos x = cos y, implies x = 2nπ ± y, where n Z.

• tan x = tan y, implies x = nπ + y, where n Z.

given,

sin x tan x – 1 = tan x – sin x

sin x tan x – tan x + sin x – 1 = 0

tan x(sin x – 1) + (sin x – 1) = 0

(sin x – 1)(tan x + 1) = 0

sin x = 1 or tan x = -1

sin x = sin π/2 or tan x = tan (- π/4 )

If sin x = sin y, implies x = nπ + (– 1)ny, where n Z.

and tan x = tan y, implies x = nπ + y, where n Z.

x = nπ + (-1)n (π /2) or x = mπ + (- π/4) Rate this question :

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