Q. 7 F5.0( 1 Vote )

# Solve the followi

Ideas required to solve the problem:

The general solution of any trigonometric equation is given as –

• sin x = sin y, implies x = nπ + (– 1)ny, where n Z.

• cos x = cos y, implies x = 2nπ ± y, where n Z.

• tan x = tan y, implies x = nπ + y, where n Z.

given,

4 sin x cos x + 2 sin x + 2 cos x + 1 = 0

2sin x (2cos x + 1) + 1(2cos x + 1) = 0

(2cos x + 1)(2sin x + 1) = 0

cos x = -1/2 or sin x = -1/2

cos x = cos (π - π/3) or sin x = sin (- π/6)

cos x = cos 2π/3 or sin x = sin (-π/6)

If sin x = sin y, implies x = nπ + (– 1)ny, where n Z.

And cos x = cos y, implies x = 2nπ ± y, where n Z.

x = 2nπ ± 2π/3 or x = mπ + (-1)m (-π/6)

Hence,

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses
RELATED QUESTIONS :

Solve the followiRD Sharma - Mathematics

3sin2 RD Sharma - Mathematics

Solve the followiRD Sharma - Mathematics

Solve : <span lanRD Sharma - Mathematics

Solve the followiRD Sharma - Mathematics

Solve : <span lanRD Sharma - Mathematics

Solve the followiRD Sharma - Mathematics

Solve the followiRD Sharma - Mathematics

Find the general RD Sharma - Mathematics

Find the general RS Aggarwal - Mathematics