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The monomials are (i)5x,6y,7z and (ii)3x2y,4xy2,7x3y3

(i) The given monomial is 5x,6y,7z .

Therefore the product of above terms is (5x)×(6y)×(7z) = 210xyz

(ii) The given monomial is 3x2y,4xy2,7x3y3 .

Therefore the product of above terms is (3x2y)×(4xy2)×(7x3y3) = 84x6y6

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