Q. 74.4( 29 Votes )

<span lang="EN-US

Answer :

The monomials are (i)5x,6y,7z and (ii)3x2y,4xy2,7x3y3

(i) The given monomial is 5x,6y,7z .


Therefore the product of above terms is (5x)×(6y)×(7z) = 210xyz


(ii) The given monomial is 3x2y,4xy2,7x3y3 .


Therefore the product of above terms is (3x2y)×(4xy2)×(7x3y3) = 84x6y6


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

<span lang="EN-USAP - Mathematics

<span lang="EN-USAP - Mathematics

<span lang="EN-USAP - Mathematics

<span lang="EN-USAP - Mathematics

<span lang="EN-USAP - Mathematics

<span lang="EN-USAP - Mathematics

<span lang="EN-USAP - Mathematics

<span lang="EN-USAP - Mathematics

<span lang="EN-USAP - Mathematics

<span lang="EN-USAP - Mathematics