Steps of construction:
1. Draw a line segment BC = 7 cm.
2. Draw ∠ABC = 45° and ∠ACB = 30° i.e. ∠BAC = 105°.
We obtain ΔABC.
3. Draw a ray BX making an acute angle with BC. Mark four points B1, B2, B3,B4 at equal distances.
4. Through B3 draw B3C and through B4 draw B4C1 parallel to B3C.
Then draw A1C1 parallel to AC.
∴ A1BC1 is the required triangle.
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