Answer :

We are given that


Circumference of a circle = Perimeter of square


Let r be the radius of the circle and a be the side of square.


from the given condition, we have 2π r = 4a


(22/7)r = 2a


11r = 7a


a = (11/7)a


r = (7/11)a …………..(i)


Now, area of circle = A1 = πr2 and area of square = A2 = a2


From equation (i ), we have


A1 = π × (7/11)2


= (22/7) × (49/121)a2


= (14/11)a2 and A2 = a2


A1 = (14/11) A2


A1 > A2


Hence, Area of the circle > Area of the square.

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Trigo Marathon Part 2Trigo Marathon Part 2Trigo Marathon Part 245 mins
Trigo Marathon Part 1Trigo Marathon Part 1Trigo Marathon Part 146 mins
Application of Trigo Important QuestionsApplication of Trigo Important QuestionsApplication of Trigo Important Questions44 mins
How to Revise ChemistryHow to Revise ChemistryHow to Revise Chemistry45 mins
Nelson Mandela : Long Walk to FreedomNelson Mandela : Long Walk to FreedomNelson Mandela : Long Walk to Freedom42 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

The cost of fenciRS Aggarwal - Mathematics