# <span lang="EN-US

We are given that

Circumference of a circle = Perimeter of square

Let r be the radius of the circle and a be the side of square.

from the given condition, we have 2π r = 4a

(22/7)r = 2a

11r = 7a

a = (11/7)a

r = (7/11)a …………..(i)

Now, area of circle = A1 = πr2 and area of square = A2 = a2

From equation (i ), we have

A1 = π × (7/11)2

= (22/7) × (49/121)a2

= (14/11)a2 and A2 = a2

A1 = (14/11) A2

A1 > A2

Hence, Area of the circle > Area of the square.

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