Q. 34.6( 28 Votes )

# Find the area of

area of trapezium ABCD = area of rectangle ADCE + area(ΔBEC)…(i)

let us find area of rectangle ADCE

length = AD = 8 cm

breadth = AE = 3 cm

area of rectangle = length × breadth

area of rectangle ADCE = length × breadth

= AD × AE

= 8 × 3

= 24 sq. cm

Therefore, area of rectangle ADCE = 24 sq. cm

From figure EC || AD

BEC = EAD = 90° …corresponding angles

BEC = 90°

And since ADCE is a rectangle EC = AD

EC = 8 cm

Now let us find area(ΔBEC)

area of triangle = × base × height

area(ΔBEC) = × EC × BE

area(ΔBEC) = × 8 × 3

area(ΔBEC) = 4 × 3

area(ΔBEC) = 12 cm2

From (i)

area of trapezium ABCD = area of rectangle ADCE + area(ΔBEC)…(i)

= 24 + 12

= 36 sq. cm

therefore, area of trapezium ABCD = 36 sq. cm

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses
RELATED QUESTIONS :

In the figure, diAP- Mathematics

ABCD is a paralleAP- Mathematics

In the figure, XYAP- Mathematics

In a triangle ABCAP- Mathematics

In the figure, ∆AAP- Mathematics

P and Q are any tAP- Mathematics

Show that the diaAP- Mathematics

In the figure, ∆AAP- Mathematics

A farmer has a fiAP- Mathematics

In the figure, ifAP- Mathematics