2. Join the point of intersection from A and B.
Hence, this gives the required triangle ABC
3. Dividing the base, draw a ray AX which is at an acute angle from AB
4. Plot seven points on AX such that:
AA1 = A1A2 = A2A3 = A3A4 = A4A5 = A5A6 = A6A7.
5. Join A5 to B.
6. Draw a line from point A7that is parallel to A5B and joins AB’ (AB extended to AB’).
7. Draw a line B’C’ || BC.
Hence, triangle AB’C’ is the required triangle.
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