Answer :


Ideas required to solve the problem:


The general solution of any trigonometric equation is given as –


• sin x = sin y, implies x = nπ + (– 1)ny, where n Z.


• cos x = cos y, implies x = 2nπ ± y, where n Z.


• tan x = tan y, implies x = nπ + y, where n Z.


Given,



{ sin θ = cos (π/2 – θ) }


If cos x = cos y then x = 2nπ ± y, where n Z


Clearly on comparing we have y = 3x



, or


or



Hence,


…ans


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