Answer :

Step 1: Draw a line segment AB of 5 cm.

Step 2: Taking A and B as Center, draw arcs of 6 cm and 5 cm radius respectively. Let these arcs intersect each other at point C. ABC is the required triangle having length of sides as 5 cm , 6 cm , 7 cm respectively.

Step 3: Draw a ray AX making acute angle with line AB on the opposite side of vertex C.

Step 4: Locate 7 points, A1,A2,A3,A4, A5,A6,A7( as 7 is greater between 5 and 7), on line AX such that AA1=A1 A2=A2 A3=A3 A4=A4 A5=A5 A6=A6 A7

Step 5: Join BA5 and draw a line through A7 parallel to BA5 to intersect extended line segment AB at point B′.

Step 6: Draw a line through B′ parallel to BC intersecting the extended line segment AC at C′.AB’C’ is the required triangle.


∆AB' C'~∆ABCby AAA Similarity Condition


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses