Answer :

The equation of the given circle is x^{2} +y^{2} = 25.

x^{2} +y^{2} = 25

(x– 0)^{2} +(y – 0)^{2} = 5^{2}, which is of the form (x – h)^{2}+ (y – k)^{2} =r^{2},

Where, h=0, k=0 and r=5.

Distance between point (-2.5, 3.5) and the centre (0,0)

=

=

=

=4.3 (approx.) <5

Since, the distance between point (-2.5, -3.5) and the centre (0, 0) of the circle is less than the radius of the circle, point (-2.5, -3.5) lies inside the circle.

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