# Find the equation of a circle with centre (2,2) and passes through the point (4,5).

The centre of the circle is given as (h,k) = (2,2).

Since, the circle passes through point (4,5), the radius (r) of the circle is the distance between the points (2,2) and (4,5). r = = = = Thus, the equation of the circle is

(x– h)2+ (y – k)2 =r2 (x –h)2 + (y – k)2 =  (x –2)2 + (y – 2)2 =  x2 - 4x+4 +y2- 4y+4 =13 x2 +y2 – 4x -4y = 5

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