Q. 10 G

# A chord of ⨀(O, 5) touches ⨀(O, 3). Therefore the length of the chord =A. 8B. 10C. 7D. 6

Given chord of circle (O, 5) touches circle (O, 3).

Radius of smaller circle OM = 3 and radius of bigger circle OB = 5

In right angled ΔOMB,

OB2 = OM2 + MB2

52 = 32 + MB2

MB2 = 25 – 9 = 16

MB = 4

Length of chord AB = 2 (MB) = 2 (4) = 8

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