Q. 10 G

# A chord of ⨀(O, 5) touches ⨀(O, 3). Therefore the length of the chord =

A. 8

B. 10

C. 7

D. 6

Answer :

Given chord of circle (O, 5) touches circle (O, 3).

Radius of smaller circle OM = 3 and radius of bigger circle OB = 5

In right angled ΔOMB,

⇒ OB^{2} = OM^{2} + MB^{2}

⇒ 5^{2} = 3^{2} + MB^{2}

⇒ MB^{2} = 25 – 9 = 16

⇒ MB = 4

Length of chord AB = 2 (MB) = 2 (4) = 8

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