Q. 10 A

P is in exterior of (O, 15). A tangent from P touches the circle at T. If PT = 8, then OP = ………..
A. 17

B. 13

C. 23

D. 7

Answer :

Given P is in exterior of circle (O, 15) and a tangent from P touches the circle at T.


Thus, OTP = 90°



By Pythagoras Theorem,


OP2 = OT2 + TP2


OP2 = 152 + 82


= 225 + 64


= 289


OP = 17

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