Q. 9

# A wire of length

Given a wire of length 86 cm is bent into a rectangle.

Perimeter of rectangle = 86 cm

It is also given that length of the rectangle is 7 cm more than its breadth.

Let length and breadth of the rectangle be ‘l’ cm and ‘b’ cm.

l = b + 7

We know, Perimeter of rectangle = 2 (length + breadth)

86 = 2(l + b)

86 = 2[(b + 7) + b]

86 = 2(2b + 7)

4b + 14 = 86

4b = 72 We have l = b + 7

l = 18 + 7

l = 25 cm

Thus, length and breadth of rectangle are 25 cm and 18 cm.

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