Q. 74.2( 6 Votes )

If one end of a d

Answer :

Equation of the circle,


x2 - 4x + y2 - 6y + 11 = 0


x2 - 4x + 4 + y2 - 6y + 9 +11 – 13 = 0


x2 - 2(2)x + 22 + y2 - 2(3)y + 32 +11 – 13 = 0


(x – 2)2 + (y – 3)2 = 2


(x – 2)2 + (y – 3)2 = (√2)2


Since, the equation of a circle having centre (h,k), having radius as "r" units, is


(x – h)2 + (y – k)2 = r2


Centre = (2,3)


the centre point is the mid-point of the two ends of the diameter of a circle.


Let the points be (p,q)



p + 3 = 4 & q + 4 = 6


p = 1 & q = 2


Hence, the other ends of the diameter are (1,2).


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