Q. 225.0( 1 Vote )

# Find the equation of the hyperbola with eccentricity 3/2 and foci at (± 2, 0).

Answer :

Foci = (± ae,0) = (± 2, 0)

the hyperbola lies on x – axis,

Equation is

ae = 2 (given)

b^{2} = a^{2} (e^{2} - 1)

Equation is

Hence, the required equation is

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