Answer :

In ΔABC, we have ∠A = 90°.

Using Pythagoras theorem, which states the square of hypotenuse in a right-angled triangle is equal to the sum of the squares of the other two sides,

BC^{2} = AB^{2} + AC^{2}

⇒ BC^{2} = 5^{2} + 12^{2}

⇒ BC^{2} = 25 + 144

⇒ BC^{2} = 169

We know,

As ΔABC is right-angled with ∠A = 90°, we have base = AC and height = AB

∴ Area of ΔABC = 30 cm^{2}

But, it is given that AD ⊥ BC. So area of ΔABC can also be expressed in terms of AD and BC.

Here, we have base = BC and height = AD.

We already found Area of ΔABC = 30 cm^{2}

⇒ 13 × AD = 60

Thus, **length of AD is 4.615 cm.**

Rate this question :

Area of a trianglNCERT - Exemplar Mathematics

<span lang="EN-USNCERT Mathematics

<img style=NCERT Mathematics

<span lang="EN-USNCERT Mathematics

In the given triaNCERT - Exemplar Mathematics

Find the area of NCERT - Exemplar Mathematics

In Fig. 9.32, areNCERT - Exemplar Mathematics

Ratio of the areaNCERT - Exemplar Mathematics

Area of an isosceNCERT - Exemplar Mathematics

In Fig. 9.41, areNCERT - Exemplar Mathematics