# <span lang="EN-US

Given :- Right trapezium

RS = 8 cm

PT = 8cm

TQ = 8 cm

RQ = 17 cm

Here PQ = PT + TQ = 8 + 8 = 16

We know that area of trapezium is x (sum of parallel sides) x height

That is x (AB + DC) x RT

Consider TQR

By Pythagoras theorem

RQ2 = TQ2 + RT2

172 = 82 + RT2

RT2 = 17 2 - 82 = 289 – 64 = 225

RT = 15 cm

Area of trapezium = x (RS + PQ) x RT

= x (8 + 16) x 15 = 180 cm2

Area of trapezium PQRS = 180cm2

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses
RELATED QUESTIONS :

In Q. No. 1, if ARD Sharma - Mathematics

<span lang="EN-USRS Aggarwal & V Aggarwal - Mathematics

<span lang="EN-USRS Aggarwal & V Aggarwal - Mathematics

<span lang="EN-USRS Aggarwal & V Aggarwal - Mathematics

ABCD is a paralleRD Sharma - Mathematics

In Δ ABC, ERD Sharma - Mathematics

P is the mid-poinRD Sharma - Mathematics

Diagonals of a quRD Sharma - Mathematics

ABCD is a trapeziRD Sharma - Mathematics