Q. 5B4.1( 7 Votes )

# Calculate the area of trap. PQRS, given in Fig. (ii).

Answer :

Given :- Right trapezium

RS = 8 cm

PT = 8cm

TQ = 8 cm

RQ = 17 cm

Here PQ = PT + TQ = 8 + 8 = 16

We know that area of trapezium is x (sum of parallel sides) x height

That is x (AB + DC) x RT

Consider TQR

By Pythagoras theorem

RQ^{2} = TQ^{2} + RT^{2}

17^{2} = 8^{2} + RT^{2}

RT^{2} = 17 ^{2} - 8^{2} = 289 – 64 = 225

RT = 15 cm

Area of trapezium = x (RS + PQ) x RT

= x (8 + 16) x 15 = 180 cm^{2}

Area of trapezium PQRS = 180cm^{2}

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