Q. 5B4.1( 7 Votes )

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Answer :

Given :- Right trapezium

RS = 8 cm

PT = 8cm

TQ = 8 cm

RQ = 17 cm

Here PQ = PT + TQ = 8 + 8 = 16

We know that area of trapezium is x (sum of parallel sides) x height

That is x (AB + DC) x RT

Consider TQR

By Pythagoras theorem

RQ2 = TQ2 + RT2

172 = 82 + RT2

RT2 = 17 2 - 82 = 289 – 64 = 225

RT = 15 cm

Area of trapezium = x (RS + PQ) x RT

= x (8 + 16) x 15 = 180 cm2

Area of trapezium PQRS = 180cm2

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