Answer :

Here, Let ABCD be Rhombus with diagonals AC and BD

Here let AC = 24 and BD = 16

We know that, in a Rhombus, diagonals are perpendicular bisectors to each other

if we consider ABC AC is base and OB is height

Similarly, in ADC AC is base and OD is height

Now, Area of Rhombus = Area of ABC + Area of ADC

= x AC x OB + x AC x OD

= x 24 x + x 24 x (Since AC and BC are perpendicular bisectors OB = OD = )

= x 24 x + x 24 x = 96 + 96 = 192 cm^{2}

Area of Rhombus ABCD is 192cm^{2}

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