Answer :
Let ABCD be a rhombus in which diagonals intersect at point O and a circle is drawn is drawn taking side CD as diameter
Now,
∠COD = 900
(Since, diagonals of rhombus intersect at 900)
Hence,
∠AOB = ∠BOC = ∠COD = ∠DOA = 900
Hence, point O has to lie on the circle
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