Q. 54.1( 50 Votes )

Prove that the ci

Answer :

Let ABCD be a rhombus in which diagonals intersect at point O and a circle is drawn is drawn taking side CD as diameter

Now,


COD = 900


(Since, diagonals of rhombus intersect at 900)


Hence,


AOB = BOC = COD = DOA = 900


Hence, point O has to lie on the circle


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