Answer :
Given: ∠B = 35°
∠C = 65°
The bisector of ∠ABC meets BC in P
We have to arrange AP, BO and CP in descending order
In Δ ACP, we have
∠ACP > ∠CAP
AP > CP (i)
In Δ ABP, we have
∠BAP > ∠ABP
BP > AP (ii)
From (i) and (ii), we have
BP > AP > CP
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