Answer :


Given: B = 35°


C = 65°


The bisector of ABC meets BC in P


We have to arrange AP, BO and CP in descending order


In Δ ACP, we have


ACP > CAP


AP > CP (i)


In Δ ABP, we have


BAP > ABP


BP > AP (ii)


From (i) and (ii), we have


BP > AP > CP


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