Q. 33.9( 62 Votes )

The lengths of tw

Answer :

Let AB and CD be two parallel chords in a circle centered at O

Join OB and OD

Distance of the smaller chord AB from the centre of the circle = 4cm

OM = 4cm

MB = =

In ΔOMB,

OM² + MB² = OB²

(4)² + ² = OB²

16 + 9 = OB²

OB = 5cm

In ΔOND,

ON² + ND² = OD²

(ON)² + ² = 5²

(ON)²= 9

ON = 3 cm

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