Q. 54.4( 258 Votes )

In Fig. 10.39, A,

Answer :

In ΔCDE,

CDE + DCE = CEB (Exterior angle)


CDE + 20° = 130°


CDE = 110°


However, BAC = CDE (Angles in the same segment of a circle)


BAC = 110°
As angles in same segment are equal.
So,

BAC = ∠BDC  =110°

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