Q. 44.4( 259 Votes )

In Fig. 10.38, <s

Answer :

BAC = BDC (Angles in the segment of the circle)


In triangle ABC,


BAC + ABC + ACB = 180o (Sum of all angles in a triangle)


BAC + 69o + 31o = 180o


BAC = 180o – 100o


BAC = 80o


Thus,


BDC = 80o

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