Answer :

It is given in the question that,

Ac is the common hypotenuse

So, ∠B = ∠D = 90^{o}

We have to prove that,

∠CAD = ∠CBD

**Proof:** We know that,

∠ABC and ∠ADC are 90^{o} as these angles are in a circle

Thus, both the triangles are lying in the circle and both have same diameter i.e. AC

Points A, B, C and D are concyclic

Therefore, CD is the chord

So,

∠CAD = ∠CBD (As, angles made by a chord in the same segment are equal)

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