Answer :

Consider a ΔABC

Two circles are drawn while taking AB and AC as the diameter

Join AD

∠ADB = 90° (Angle subtended by semi-circle)

∠ADC = 90° (Angle subtended by semi-circle)

∠BDC =∠ ADB + ∠ADC = 90° + 90° = 180°

Therefore, BDC is a straight line

**Thus, Point D lies on the third side BC of ΔABC.**

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