Q. 14.4( 303 Votes )

In Fig. 10.36, A,

Answer :

∠AOC = ∠AOB + ∠BOC

= 60° + 30°


= 90°


We know that angle subtended by an arc at the centre is double the angle subtended by it any point on the remaining part of the circle


∠ADC = ∠AOC


=  × 90o


= 45o

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