Q. 2 A4.7( 3 Votes )

Find the area of the quadrilateral whose vertices are

(1, 1), (7, -3), (12, 2) and (7, 21)

Answer :

Given (1, 1), (7, -3), (12, 2) and (7, 21)



Let us Assume A(x1, y1) = (1, 1)


Let us Assume B(x2, y2) = (7, -3)


Let us Assume C(x3, y3) = (12, 2)


Let us Assume D(x4, y4) = (7, 21)


Let us join Ac to from two triangles ∆ABC and ∆ACD


Now


Area of triangle


Then,


Area of given triangle ABC




= 25 square units


Area of given triangle ABC




= 107 square units


Area of quadrilateral ABCD = Area of ABC + Area of ACD


= 25 + 107


= 132 sq units.


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Section Formula30 mins
Previous Year RMO Questions43 mins
NCERT | Most Important Proofs for Boards28 mins
Know About Important Proofs in Triangles33 mins
Champ Quiz | Previous Year NTSE QuestionsFREE Class
Measuring distance by Distance formula49 mins
Champ Quiz | Distance Formula30 mins
Coordinate Geometry Important Questions38 mins
Imp. Qs. on Distance Formula68 mins
Geometry of Temples36 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses