Q. 54.5( 57 Votes )

Find the po

Answer :

Given equation of line


4x + 3y = 12


4x + 3y – 12 = 0


Comparing above equation with general equation of line Ax + By + C = 0, we obtain A = 4, B = 3, and C = -12


Let (a, 0) be the point on the x-axis whose distance from the given line is 4 units.


Perpendicular distance (d) of a line Ax + By + C = 0 from a point (x1, y1) is given by





|4a – 12| = 4 × 5


(4a – 12) = 20


4a – 12 = 20 or - (4a – 12) = 20


4a = 20 + 12 or 4a = -20 + 12


a = 32/4 or a = -8/4


a = 8 or a = -2


The required points on the x – axis are (-2, 0) and (8, 0)


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