Q. 44.6( 30 Votes )

# A cylindrical tub of radius 5 cm and length 9.8 cm is full of water. A solid in the form of right circular cone mounted on a hemisphere is immersed into the tub. The radius of the hemisphere is 3.5 cm and height of cone outside the hemisphere is 5 cm. Find the volume of water left in the tub

Answer :

Given that, radius of cylinder(r) is 5 cm and height(h) is 9.8 cm. Also, radius of hemisphere(R) is 3.5 cm and height(H) of cone outside the hemisphere is 5 cm.

⇒ vol. of solid = vol. of hemisphere + vol. of cone

= 154 cm^{3}

⇒ vol. of tub = πr^{2}h

= 770 cm^{3}

⇒ the volume of water left in the tub = vol.of tub-vol. of solid

= 770-154

= 616 cm^{3}

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