Answer :
Let P and Q be the points of trisection of AB, i.e. AP = PQ = QB
∴ P divides AB internally in the ratio 1: 2.
∴ the coordinates of P, by applying the section formula, are
…(i)
Here, m1 = 1, m2 = 2
(x1, y1) = (1, -2) and (x2, y2) = (-3, 4)
Putting the above values in the above formula, we get
Now, Q also divides AB internally in the ratio 2: 1. So, the coordinates of Q are
…(i)
Here, m1 = 2, m2 = 1
(x1, y1) = (1, -2) and (x2, y2) = (-3, 4)
Putting the above values in the above formula, we get
Therefore, the coordinates of the points of trisection of the line segment joining A and B are
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