Answer :
Since , H is the orthocenter of the ΔABC
So, ADꞱBC , BEꞱAC and CFꞱAB
X, Y and Z are the midpoints of AH, BH and CH respectively
∴ XYZ is a triangle.
Hence, XZ||AC
So, ∠HOX=∠HEA=90°
Similarly, XY||AB
And ∠HPX=∠HFA=90°
And YZ||BC
So, ∠HQZ=∠HDC=90°
Hence, HO, HP and HQ are the altitudes of ∆XYZ
So, H is the orthocenter of ∆XYZ
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