Q. 63.7( 7 Votes )
If AOB is a diameter of a circle and C is a point on the circle, then AC2 + BC2 = AB2
Let AB be the diameter of the circle with center O and C be any point on circle.
Since, diameter subtends a right angle to the circle,
∴ ∠ACB = 90°
Now, in right angled triangle ACB, by Pythagoras theorem, we have:
(AB)2 = (AC)2 + (AB)2
Thus, the statement is true.
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