Q. 63.7( 7 Votes )

# If AOB is a diameter of a circle and C is a point on the circle, then AC^{2} + BC^{2} = AB^{2}

Answer :

TRUE

Let AB be the diameter of the circle with center O and C be any point on circle.

Since, diameter subtends a right angle to the circle,

∴ ∠ACB = 90°

Now, in right angled triangle ACB, by Pythagoras theorem, we have:

(AB)^{2} = (AC)^{2} + (AB)^{2}

Thus, the statement is true.

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