Answer :

Given points are A(3, 2) and B(- 5, - 2).



We need to find a point on x - axis which is equidistant from these points.


Let us assume the point on x - axis be S(x, o).


We know that distance between the points (x1, y1) and (x2, y2) is .


From the problem,


SA = SB


SA2 = SB2


(x - 3)2 + (0 - 2)2 = (x + 5)2 + (0 - (- 2))2


(x - 3)2 + (- 2)2 = (x + 5)2 + (2)2


x2 - 6x + 9 + 4 = x2 + 10x + 25 + 4


16x = - 16



x = - 1


The point on x - axis is (- 1, 0).


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