# If tangents PA and PB from a point P to a circle with centre O are inclined to each other at angle of 80°, then ∠ POA is equal toA. 50° B. 60°C. 70° D. 80°

Given: PA and PB are tangents.

Therefore, the radius drawn to these tangents will be perpendicular to the tangents.

Thus, OA PA and OB PB

OBP = 90°

OAP = 90°

Sum of all interior angles = 360°

OAP + APB +PBO + BOA = 360° 90° + 80° +90° + BOA = 360°

BOA = 100°

In ΔOPB and ΔOPA,

AP = BP (Tangents from a point)

OA = OB (Radii of the circle)

OP = OP (Common side)

Therefore, ΔOPB ΔOPA (SSS congruence criterion)

And thus, POB = POA

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