Q. 2 4.4( 217 Votes )

In Fig. 10.11, if TP and TQ are the two tangents to a circle with centre O so that POQ = 110°, then PTQ is equal to

A. 60° B. 70°

C. 80° D. 90°


Answer :

Given: TP and TQ are tangents.


Therefore, radius drawn to these tangents from centre of the circle will be perpendicular to the tangents.


Thus, OP TP and OQ TQ

And therefore,

OPT = 90°

OQT = 90°


In quadrilateral POQT,


Sum of all interior angles = 360°


OPT + POQ +OQT + PTQ = 360°


90°+ 110° + 90° + PTQ = 360°


PTQ = 70°

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