# In Fig. 10.11, if TP and TQ are the two tangents to a circle with centre O so that ∠ POQ = 110°, then ∠ PTQ is equal toA. 60° B. 70°C. 80° D. 90°

Given: TP and TQ are tangents.

Therefore, radius drawn to these tangents from centre of the circle will be perpendicular to the tangents.

Thus, OP TP and OQ TQ

And therefore,

OPT = 90°

OQT = 90°

Sum of all interior angles = 360°

OPT + POQ +OQT + PTQ = 360°

90°+ 110° + 90° + PTQ = 360°

PTQ = 70°

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