Q. 19

# In Fig 10.57, a circle is inscribed in a quadrilateral ABCD in which . If AD = 23 cm, AB = 29 cm and DS = 5 cm, find the radius r of the circle.

AD = DS = 5cm (tangent from an external point)

So,

AR + 5 = 23 cm

AR = 18 cm ------(i)

and AQ = AR

since AR = 18 cm

So, AQ + QB = AB

Now OP and OQ are radius of the circle. So from tangent P and Q

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