Q. 163.6( 35 Votes )

Prove that the pe

Answer :

Draw a circle with centre O, draw a tangent PR touching circle at P.
Draw QP perpendicular to RP at a point P, QP lies in the circle.
Now,
∠OPR = 90º
Also, ∠QPR = 90º 
Therefore,
∠OPR = ∠QPR
This is possible only when O lies on QP.
Hence, it is proved that the perpendicular at the point of contact to the tangent to a circle passes through the centre.

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Area Related to Circles- Important Formula and ConceptsArea Related to Circles- Important Formula and ConceptsArea Related to Circles- Important Formula and Concepts59 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses