Q. 144.3( 88 Votes )

Find equati

Answer :

Given point = (0, 2) and θ = 2π/3


We know that m = tanθ


m = tan (2π/3) = -3


We know that the point (x, y) lies on the line with slope m through the fixed point (x0, y0), if and only if, its coordinates satisfy the equation y – y0 = m (x – x0)


y 2 = -3 (x 0)


y 2 = -3 x


√3 x + y – 2 = 0


Given, equation of line parallel to above obtained equation crosses the y-axis at a distance of 2 units below the origin.


So, the point = (0, -2) and m = -√3


From point slope form equation,


y (-2) = -3 (x 0)


y + 2 = -3 x


3 x + y + 2 = 0


Ans. The equation of line is √3 x + y – 2 = 0 and the line parallel to it is √3 x + y + 2 = 0.


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