Q. 11 A4.3( 3 Votes )

# If the point (x, y) on the tangent is equidistant from the points (2, 3) and (6, - 1), find the relation between x and y.

Given points are A(2, 3) and B(6, - 1). It is told that S(x, y) is equidistant from A and B.

So, we get SA = SB,

We know that distance between two points (x1, y1) and (x2, y2) is .

Now,

SA = SB

SA2 = SB2

(x - 2)2 + (y - 3)2 = (x - 6)2 + (y - (- 1))2

(x - 2)2 + (y - 3)2 = (x - 6)2 + (y + 1)2

x2 - 4x + 4 + y2 - 6y + 9 = x2 - 12x + 36 + y2 + 2y + 1

8x - 8y = 24

x - y = 3

The relation between x and y is x - y = 3.

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