Q. 9

# In Fig. 10.8, BC is a diameter of the circle and BAO = 60 �. Then ADC is equal to:

A. 30 �

B. 45 �

C. 60 �

D. 120 �

Answer :

Given: ∠BAO = 60°

Since, OA and OB are radius of the circle, therefore OA = OB

⇒ ∠ ABO = ∠BAO = 60° (∵ given that ∠BAO = 60°)

Since angle in the same segment are equal, therefore

∠ABC = ∠ADC (angles in the same segment AC are equal)

∠ABC = ∠ABO = 60°

∴ ∠ADC = 60°

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