# The base of an equilateral triangle with side 2a lies along the y-axis such that the mid-point of the base is at the origin. Find vertices of the triangle. Let ABC be the given equilateral triangle with side 2a

AB= BC = AC = 2a

Assuming that the base AB lies on the y axis such that the mid-point of AB is at the origin

i.e.BO = OA = a and O is the origin

⇒ Co-ordinates of point A are (0,a) and that of B are (0,-a)

Since the line joining a vertex of an equilateral ∆ with the mid-point of its opposite side is perpendicular

Vertex of A lies on the y –axis

On applying Pythagoras theorem

(AC)2 = OA2 + OC2

(2a)2= a2 + OC2

4a2 – a2 = OC2

3a2= OC2

OC = Co-ordinates of point C = Thus, the vertices of the given equilateral triangle are (0, a) , (0, -a) , ( Or (0, a), (0, -a) and ( Rate this question :

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