# Draw a quadrilateral in the Cartesian plane, whose vertices are (– 4, 5), (0, 7), (5, – 5) and (– 4, –2). Also, find its area.

Let ABCD be the given quadrilateral with vertices A(-4,5) , B(0,7), C(5.-5) and D(-4,-2). Plotting the points on the Cartesian plane and joining AB, BC, CD, AD gives us the required quadrilateral. To find the area, draw diagonal AC

area (ABCD) = ar ( ∆ABC) + ar(∆ADC)

area ∆ with vertices ( x1,y1) , (x2, y2) and (x3,y3) is  unit2 unit2 Area ∆ ACD =   Since area cannot be negative area ∆ ACD = Area (ABCD) = Rate this question :

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